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Language pairs:
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Criteria:
max f(S) / f(T) = 10, max f(T) / f(S) = 10, min f(S) = min f(T) = 5, min p(T|S) = 0.008,
f
1
(S) ∈ [1, 10] → min p(T|S) = 0.3, f
2
(S) ∈ [10, 100] → min p(T|S) = 0.14, f
3
(S) ∈ [100, 1000] → min p(T|S) = 0.04
~
prob
freq
compo
mate
0.291
345
inbreng
0.171
47
aanvoer
0.107
20
voedselinname
0.094
22
bijdrage
0.091
424
aanvoer
bijdrage
inbreng
mate
voedselinname
.