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Language pairs:
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Criteria:
max f(S) / f(T) = 10, max f(T) / f(S) = 10, min f(S) = min f(T) = 5, min p(T|S) = 0.008,
f
1
(S) ∈ [1, 10] → min p(T|S) = 0.3, f
2
(S) ∈ [10, 100] → min p(T|S) = 0.14, f
3
(S) ∈ [100, 1000] → min p(T|S) = 0.04
~
prob
freq
compo
cependant
0.222
814
toutefois
0.171
761
mais
0.075
6458
néanmoins
0.032
308
pourtant
0.019
411
contre
0.015
1515
falloir
0.013
2011
or
0.010
303
cependant
contre
falloir
mais
néanmoins
or
pourtant
toutefois
.